10120221214111 has 2 divisors, whose sum is σ = 10120221214112. Its totient is φ = 10120221214110.

The previous prime is 10120221214109. The next prime is 10120221214163. The reversal of 10120221214111 is 11141212202101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10120221214111 - 2¹ = 10120221214109 is a prime.

Together with 10120221214109, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10120221214171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060110607055 + 5060110607056.

It is an arithmetic number, because the mean of its divisors is an integer number (5060110607056).

Almost surely, 2^{10120221214111} is an apocalyptic number.

10120221214111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10120221214111 is an equidigital number, since it uses as much as digits as its factorization.

10120221214111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 19.

Adding to 10120221214111 its reverse (11141212202101), we get a palindrome (21261433416212).

The spelling of 10120221214111 in words is "ten trillion, one hundred twenty billion, two hundred twenty-one million, two hundred fourteen thousand, one hundred eleven".