Base | Representation |
---|---|
bin | 11101011101011000000… |
… | …11111010100101011111 |
3 | 10120202200020102222112222 |
4 | 32232230003322211133 |
5 | 113040443212201421 |
6 | 2053000005015555 |
7 | 133062234141302 |
oct | 16565403724537 |
9 | 3522606388488 |
10 | 1012204022111 |
11 | 360300867387 |
12 | 1442090b45bb |
13 | 745b17952b9 |
14 | 36dc31b2b39 |
15 | 1b4e2d87cab |
hex | ebac0fa95f |
1012204022111 has 2 divisors, whose sum is σ = 1012204022112. Its totient is φ = 1012204022110.
The previous prime is 1012204022069. The next prime is 1012204022113. The reversal of 1012204022111 is 1112204022101.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1012204022111 is a prime.
It is a super-3 number, since 3×10122040221113 (a number of 37 digits) contains 333 as substring.
Together with 1012204022113, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1012204022111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1012204022113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506102011055 + 506102011056.
It is an arithmetic number, because the mean of its divisors is an integer number (506102011056).
Almost surely, 21012204022111 is an apocalyptic number.
1012204022111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012204022111 is an equidigital number, since it uses as much as digits as its factorization.
1012204022111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 1012204022111 its reverse (1112204022101), we get a palindrome (2124408044212).
The spelling of 1012204022111 in words is "one trillion, twelve billion, two hundred four million, twenty-two thousand, one hundred eleven".
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