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1012204022111 is a prime number
BaseRepresentation
bin11101011101011000000…
…11111010100101011111
310120202200020102222112222
432232230003322211133
5113040443212201421
62053000005015555
7133062234141302
oct16565403724537
93522606388488
101012204022111
11360300867387
121442090b45bb
13745b17952b9
1436dc31b2b39
151b4e2d87cab
hexebac0fa95f

1012204022111 has 2 divisors, whose sum is σ = 1012204022112. Its totient is φ = 1012204022110.

The previous prime is 1012204022069. The next prime is 1012204022113. The reversal of 1012204022111 is 1112204022101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1012204022111 is a prime.

It is a super-3 number, since 3×10122040221113 (a number of 37 digits) contains 333 as substring.

Together with 1012204022113, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1012204022111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1012204022113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506102011055 + 506102011056.

It is an arithmetic number, because the mean of its divisors is an integer number (506102011056).

Almost surely, 21012204022111 is an apocalyptic number.

1012204022111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012204022111 is an equidigital number, since it uses as much as digits as its factorization.

1012204022111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 1012204022111 its reverse (1112204022101), we get a palindrome (2124408044212).

The spelling of 1012204022111 in words is "one trillion, twelve billion, two hundred four million, twenty-two thousand, one hundred eleven".