101222110000031 has 2 divisors, whose sum is σ = 101222110000032. Its totient is φ = 101222110000030.

The previous prime is 101222110000013. The next prime is 101222110000079. The reversal of 101222110000031 is 130000011222101.

Together with previous prime (101222110000013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101222110000031 is a prime.

It is a super-2 number, since 2×101222110000031² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101222109999970 and 101222110000015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101222110000831) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50611055000015 + 50611055000016.

It is an arithmetic number, because the mean of its divisors is an integer number (50611055000016).

Almost surely, 2^{101222110000031} is an apocalyptic number.

101222110000031 is a deficient number, since it is larger than the sum of its proper divisors (1).

101222110000031 is an equidigital number, since it uses as much as digits as its factorization.

101222110000031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 101222110000031 its reverse (130000011222101), we get a palindrome (231222121222132).

The spelling of 101222110000031 in words is "one hundred one trillion, two hundred twenty-two billion, one hundred ten million, thirty-one", and thus it is an aban number.