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10123983479 is a prime number
BaseRepresentation
bin10010110110110111…
…11011101001110111
3222010120001122111002
421123123323221313
5131213214432404
64352332033515
7505611303551
oct113333735167
928116048432
1010123983479
1143257a76a5
121b6660289b
13c545aa58c
146c07d84d1
153e3bedc1e
hex25b6fba77

10123983479 has 2 divisors, whose sum is σ = 10123983480. Its totient is φ = 10123983478.

The previous prime is 10123983473. The next prime is 10123983481. The reversal of 10123983479 is 97438932101.

10123983479 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10123983479 is a prime.

Together with 10123983481, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10123983473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5061991739 + 5061991740.

It is an arithmetic number, because the mean of its divisors is an integer number (5061991740).

Almost surely, 210123983479 is an apocalyptic number.

10123983479 is a deficient number, since it is larger than the sum of its proper divisors (1).

10123983479 is an equidigital number, since it uses as much as digits as its factorization.

10123983479 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 326592, while the sum is 47.

The spelling of 10123983479 in words is "ten billion, one hundred twenty-three million, nine hundred eighty-three thousand, four hundred seventy-nine".