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10124000141 is a prime number
BaseRepresentation
bin10010110110110111…
…11111101110001101
3222010120002111100012
421123123333232031
5131213221001031
64352332243005
7505611403253
oct113333775615
928116074305
1010124000141
114325809172
121b66610465
13c545b5038
146c08005d3
153e3c03b2b
hex25b6ffb8d

10124000141 has 2 divisors, whose sum is σ = 10124000142. Its totient is φ = 10124000140.

The previous prime is 10124000113. The next prime is 10124000143. The reversal of 10124000141 is 14100042101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8727483241 + 1396516900 = 93421^2 + 37370^2 .

It is a cyclic number.

It is not a de Polignac number, because 10124000141 - 210 = 10123999117 is a prime.

Together with 10124000143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10124000143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5062000070 + 5062000071.

It is an arithmetic number, because the mean of its divisors is an integer number (5062000071).

Almost surely, 210124000141 is an apocalyptic number.

It is an amenable number.

10124000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

10124000141 is an equidigital number, since it uses as much as digits as its factorization.

10124000141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 10124000141 its reverse (14100042101), we get a palindrome (24224042242).

The spelling of 10124000141 in words is "ten billion, one hundred twenty-four million, one hundred forty-one", and thus it is an aban number.