1012433119 has 2 divisors, whose sum is σ = 1012433120. Its totient is φ = 1012433118.

The previous prime is 1012433101. The next prime is 1012433137. The reversal of 1012433119 is 9113342101.

1012433119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (1012433101) and next prime (1012433137).

It is a cyclic number.

It is not a de Polignac number, because 1012433119 - 2¹³ = 1012424927 is a prime.

It is a super-2 number, since 2×1012433119² = 2050041640896136322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1012433093 and 1012433102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1012433519) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506216559 + 506216560.

It is an arithmetic number, because the mean of its divisors is an integer number (506216560).

Almost surely, 2^1012433119 is an apocalyptic number.

1012433119 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012433119 is an equidigital number, since it uses as much as digits as its factorization.

1012433119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

The square root of 1012433119 is about 31818.7542025140. The cubic root of 1012433119 is about 1004.1273148363.

The spelling of 1012433119 in words is "one billion, twelve million, four hundred thirty-three thousand, one hundred nineteen".