Search a number
-
+
1013114113100 = 2252231123392239
BaseRepresentation
bin11101011111000100100…
…11101000110001001100
310120212000122221101200122
432233202103220301030
5113044324203104400
62053230155244112
7133123624605635
oct16574223506114
93525018841618
101013114113100
113607285611a1
12144421a49638
13746c81b2a8b
143706bdd888c
151b547c09685
hexebe24e8c4c

1013114113100 has 72 divisors (see below), whose sum is σ = 2296091374080. Its totient is φ = 387280111680.

The previous prime is 1013114113073. The next prime is 1013114113133. The reversal of 1013114113100 is 13114113101.

1013114113100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×10131141131002 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2386781 + ... + 2779019.

Almost surely, 21013114113100 is an apocalyptic number.

1013114113100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1013114113100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1148045687040).

1013114113100 is an abundant number, since it is smaller than the sum of its proper divisors (1282977260980).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1013114113100 is a wasteful number, since it uses less digits than its factorization.

1013114113100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 393399 (or 393392 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1013114113100 its reverse (13114113101), we get a palindrome (1026228226201).

Subtracting from 1013114113100 its reverse (13114113101), we obtain a palindrome (999999999999).

The spelling of 1013114113100 in words is "one trillion, thirteen billion, one hundred fourteen million, one hundred thirteen thousand, one hundred".

Divisors: 1 2 4 5 10 20 23 25 46 50 92 100 115 230 460 575 1123 1150 2246 2300 4492 5615 11230 22460 25829 28075 51658 56150 103316 112300 129145 258290 392239 516580 645725 784478 1291450 1568956 1961195 2582900 3922390 7844780 9021497 9805975 18042994 19611950 36085988 39223900 45107485 90214970 180429940 225537425 440484397 451074850 880968794 902149700 1761937588 2202421985 4404843970 8809687940 10131141131 11012109925 20262282262 22024219850 40524564524 44048439700 50655705655 101311411310 202622822620 253278528275 506557056550 1013114113100