10132043201381 has 2 divisors, whose sum is σ = 10132043201382. Its totient is φ = 10132043201380.

The previous prime is 10132043201303. The next prime is 10132043201383. The reversal of 10132043201381 is 18310234023101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10131807302500 + 235898881 = 3183050^2 + 15359^2 .

It is an emirp because it is prime and its reverse (18310234023101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10132043201381 is a prime.

It is a super-2 number, since 2×10132043201381² (a number of 27 digits) contains 22 as substring.

Together with 10132043201383, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10132043201383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066021600690 + 5066021600691.

It is an arithmetic number, because the mean of its divisors is an integer number (5066021600691).

Almost surely, 2^{10132043201381} is an apocalyptic number.

It is an amenable number.

10132043201381 is a deficient number, since it is larger than the sum of its proper divisors (1).

10132043201381 is an equidigital number, since it uses as much as digits as its factorization.

10132043201381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 10132043201381 its reverse (18310234023101), we get a palindrome (28442277224482).

The spelling of 10132043201381 in words is "ten trillion, one hundred thirty-two billion, forty-three million, two hundred one thousand, three hundred eighty-one".