Base | Representation |
---|---|
bin | 1001001101110000110011… |
… | …0101011111101101100111 |
3 | 1022212121120111210212211111 |
4 | 2103130030311133231213 |
5 | 2312000411024421013 |
6 | 33314332453045451 |
7 | 2064005322134065 |
oct | 223341465375547 |
9 | 38777514725744 |
10 | 10132043201383 |
11 | 3256a80277634 |
12 | 11777a8926887 |
13 | 5865a842214c |
14 | 270571adb035 |
15 | 12885734e73d |
hex | 9370cd5fb67 |
10132043201383 has 2 divisors, whose sum is σ = 10132043201384. Its totient is φ = 10132043201382.
The previous prime is 10132043201381. The next prime is 10132043201417. The reversal of 10132043201383 is 38310234023101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10132043201383 - 21 = 10132043201381 is a prime.
It is a super-2 number, since 2×101320432013832 (a number of 27 digits) contains 22 as substring.
Together with 10132043201381, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10132043201381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066021600691 + 5066021600692.
It is an arithmetic number, because the mean of its divisors is an integer number (5066021600692).
Almost surely, 210132043201383 is an apocalyptic number.
10132043201383 is a deficient number, since it is larger than the sum of its proper divisors (1).
10132043201383 is an equidigital number, since it uses as much as digits as its factorization.
10132043201383 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 10132043201383 its reverse (38310234023101), we get a palindrome (48442277224484).
The spelling of 10132043201383 in words is "ten trillion, one hundred thirty-two billion, forty-three million, two hundred one thousand, three hundred eighty-three".
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