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10132043201383 is a prime number
BaseRepresentation
bin1001001101110000110011…
…0101011111101101100111
31022212121120111210212211111
42103130030311133231213
52312000411024421013
633314332453045451
72064005322134065
oct223341465375547
938777514725744
1010132043201383
113256a80277634
1211777a8926887
135865a842214c
14270571adb035
1512885734e73d
hex9370cd5fb67

10132043201383 has 2 divisors, whose sum is σ = 10132043201384. Its totient is φ = 10132043201382.

The previous prime is 10132043201381. The next prime is 10132043201417. The reversal of 10132043201383 is 38310234023101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10132043201383 - 21 = 10132043201381 is a prime.

It is a super-2 number, since 2×101320432013832 (a number of 27 digits) contains 22 as substring.

Together with 10132043201381, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10132043201381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066021600691 + 5066021600692.

It is an arithmetic number, because the mean of its divisors is an integer number (5066021600692).

Almost surely, 210132043201383 is an apocalyptic number.

10132043201383 is a deficient number, since it is larger than the sum of its proper divisors (1).

10132043201383 is an equidigital number, since it uses as much as digits as its factorization.

10132043201383 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 10132043201383 its reverse (38310234023101), we get a palindrome (48442277224484).

The spelling of 10132043201383 in words is "ten trillion, one hundred thirty-two billion, forty-three million, two hundred one thousand, three hundred eighty-three".