10132102111 has 2 divisors, whose sum is σ = 10132102112. Its totient is φ = 10132102110.

The previous prime is 10132102109. The next prime is 10132102129. The reversal of 10132102111 is 11120123101.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (11120123101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10132102111 - 2¹ = 10132102109 is a prime.

Together with 10132102109, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 10132102091 and 10132102100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10132102151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066051055 + 5066051056.

It is an arithmetic number, because the mean of its divisors is an integer number (5066051056).

Almost surely, 2^10132102111 is an apocalyptic number.

10132102111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10132102111 is an equidigital number, since it uses as much as digits as its factorization.

10132102111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 10132102111 its reverse (11120123101), we get a palindrome (21252225212).

The spelling of 10132102111 in words is "ten billion, one hundred thirty-two million, one hundred two thousand, one hundred eleven".