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101330311123159 is a prime number
BaseRepresentation
bin10111000010100011001101…
…001100110001000011010111
3111021210002020121101120121221
4113002203031030301003113
5101240143434121420114
6555302300254551211
730225605400130246
oct2702431514610327
9437702217346557
10101330311123159
112a317a41a53878
12b4465b0208507
13447053abc9101
141b045adc7295d
15baac797c8524
hex5c28cd3310d7

101330311123159 has 2 divisors, whose sum is σ = 101330311123160. Its totient is φ = 101330311123158.

The previous prime is 101330311123157. The next prime is 101330311123247. The reversal of 101330311123159 is 951321113033101.

It is a weak prime.

It is an emirp because it is prime and its reverse (951321113033101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101330311123159 - 21 = 101330311123157 is a prime.

It is a super-2 number, since 2×1013303111231592 (a number of 29 digits) contains 22 as substring.

Together with 101330311123157, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101330311123157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50665155561579 + 50665155561580.

It is an arithmetic number, because the mean of its divisors is an integer number (50665155561580).

Almost surely, 2101330311123159 is an apocalyptic number.

101330311123159 is a deficient number, since it is larger than the sum of its proper divisors (1).

101330311123159 is an equidigital number, since it uses as much as digits as its factorization.

101330311123159 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7290, while the sum is 34.

The spelling of 101330311123159 in words is "one hundred one trillion, three hundred thirty billion, three hundred eleven million, one hundred twenty-three thousand, one hundred fifty-nine".