10133111232119 has 2 divisors, whose sum is σ = 10133111232120. Its totient is φ = 10133111232118.

The previous prime is 10133111232061. The next prime is 10133111232121. The reversal of 10133111232119 is 91123211133101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10133111232119 is a prime.

It is a super-2 number, since 2×10133111232119² (a number of 27 digits) contains 22 as substring.

Together with 10133111232121, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10133111232091 and 10133111232100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10133111232199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066555616059 + 5066555616060.

It is an arithmetic number, because the mean of its divisors is an integer number (5066555616060).

Almost surely, 2^{10133111232119} is an apocalyptic number.

10133111232119 is a deficient number, since it is larger than the sum of its proper divisors (1).

10133111232119 is an equidigital number, since it uses as much as digits as its factorization.

10133111232119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 29.

The spelling of 10133111232119 in words is "ten trillion, one hundred thirty-three billion, one hundred eleven million, two hundred thirty-two thousand, one hundred nineteen".