10133313100000 has 72 divisors (see below), whose sum is σ = 24935854456296. Its totient is φ = 4053325200000.

The previous prime is 10133313099977. The next prime is 10133313100003. The reversal of 10133313100000 is 131333101.

It is a super-2 number, since 2×10133313100000² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10133313100003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 50566566 + ... + 50766565.

It is an arithmetic number, because the mean of its divisors is an integer number (346331311893).

Almost surely, 2^{10133313100000} is an apocalyptic number.

10133313100000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

10133313100000 is an abundant number, since it is smaller than the sum of its proper divisors (14802541356296).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10133313100000 is an frugal number, since it uses more digits than its factorization.

10133313100000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101333166 (or 101333138 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 10133313100000 its reverse (131333101), we get a palindrome (10133444433101).

The spelling of 10133313100000 in words is "ten trillion, one hundred thirty-three billion, three hundred thirteen million, one hundred thousand".