10134215353541 has 2 divisors, whose sum is σ = 10134215353542. Its totient is φ = 10134215353540.

The previous prime is 10134215353519. The next prime is 10134215353543. The reversal of 10134215353541 is 14535351243101.

10134215353541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8669026151041 + 1465189202500 = 2944321^2 + 1210450^2 .

It is a cyclic number.

It is not a de Polignac number, because 10134215353541 - 2³⁰ = 10133141611717 is a prime.

It is a super-2 number, since 2×10134215353541² (a number of 27 digits) contains 22 as substring.

Together with 10134215353543, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10134215353495 and 10134215353504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10134215353543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5067107676770 + 5067107676771.

It is an arithmetic number, because the mean of its divisors is an integer number (5067107676771).

Almost surely, 2^{10134215353541} is an apocalyptic number.

It is an amenable number.

10134215353541 is a deficient number, since it is larger than the sum of its proper divisors (1).

10134215353541 is an equidigital number, since it uses as much as digits as its factorization.

10134215353541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108000, while the sum is 38.

Adding to 10134215353541 its reverse (14535351243101), we get a palindrome (24669566596642).

The spelling of 10134215353541 in words is "ten trillion, one hundred thirty-four billion, two hundred fifteen million, three hundred fifty-three thousand, five hundred forty-one".