Base | Representation |
---|---|
bin | 10010111000000110… |
… | …11101000101010111 |
3 | 222011021120000110221 |
4 | 21130003131011113 |
5 | 131223343002043 |
6 | 4353342055211 |
7 | 506065334326 |
oct | 113403350527 |
9 | 28137500427 |
10 | 10134344023 |
11 | 4330633731 |
12 | 1b69b7a507 |
13 | c5679728b |
14 | 6c1d340bd |
15 | 3e4a988ed |
hex | 25c0dd157 |
10134344023 has 2 divisors, whose sum is σ = 10134344024. Its totient is φ = 10134344022.
The previous prime is 10134344021. The next prime is 10134344041. The reversal of 10134344023 is 32044343101.
10134344023 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10134344023 - 21 = 10134344021 is a prime.
Together with 10134344021, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10134344021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5067172011 + 5067172012.
It is an arithmetic number, because the mean of its divisors is an integer number (5067172012).
Almost surely, 210134344023 is an apocalyptic number.
10134344023 is a deficient number, since it is larger than the sum of its proper divisors (1).
10134344023 is an equidigital number, since it uses as much as digits as its factorization.
10134344023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 10134344023 its reverse (32044343101), we get a palindrome (42178687124).
The spelling of 10134344023 in words is "ten billion, one hundred thirty-four million, three hundred forty-four thousand, twenty-three".
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