10143313120 has 24 divisors (see below), whose sum is σ = 23963577624. Its totient is φ = 4057325184.

The previous prime is 10143313097. The next prime is 10143313127. The reversal of 10143313120 is 2131334101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10143313127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31697694 + ... + 31698013.

It is an arithmetic number, because the mean of its divisors is an integer number (998482401).

Almost surely, 2^10143313120 is an apocalyptic number.

10143313120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

10143313120 is an abundant number, since it is smaller than the sum of its proper divisors (13820264504).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10143313120 is an equidigital number, since it uses as much as digits as its factorization.

10143313120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63395722 (or 63395714 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 10143313120 its reverse (2131334101), we get a palindrome (12274647221).

It can be divided in two parts, 1014331 and 3120, that added together give a triangular number (1017451 = T₁₄₂₆).

The spelling of 10143313120 in words is "ten billion, one hundred forty-three million, three hundred thirteen thousand, one hundred twenty".