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101444103151 is a prime number
BaseRepresentation
bin101111001111010001…
…0100010101111101111
3100200211210222101100121
41132132202202233233
53130224142300101
6114334111105411
710220610435526
oct1363642425757
9320753871317
10101444103151
113a027608186
12177b1512267
139748a60551
144ca4b734bd
15298ade20a1
hex179e8a2bef

101444103151 has 2 divisors, whose sum is σ = 101444103152. Its totient is φ = 101444103150.

The previous prime is 101444103149. The next prime is 101444103263. The reversal of 101444103151 is 151301444101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 101444103151 - 21 = 101444103149 is a prime.

It is a super-2 number, since 2×1014441031512 (a number of 23 digits) contains 22 as substring.

Together with 101444103149, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101444103121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50722051575 + 50722051576.

It is an arithmetic number, because the mean of its divisors is an integer number (50722051576).

Almost surely, 2101444103151 is an apocalyptic number.

101444103151 is a deficient number, since it is larger than the sum of its proper divisors (1).

101444103151 is an equidigital number, since it uses as much as digits as its factorization.

101444103151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960, while the sum is 25.

Adding to 101444103151 its reverse (151301444101), we get a palindrome (252745547252).

The spelling of 101444103151 in words is "one hundred one billion, four hundred forty-four million, one hundred three thousand, one hundred fifty-one".