1015443141541 has 2 divisors, whose sum is σ = 1015443141542. Its totient is φ = 1015443141540.

The previous prime is 1015443141539. The next prime is 1015443141599. The reversal of 1015443141541 is 1451413445101.

1015443141541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1013805320641 + 1637820900 = 1006879^2 + 40470^2 .

It is an emirp because it is prime and its reverse (1451413445101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1015443141541 - 2¹ = 1015443141539 is a prime.

It is a super-2 number, since 2×1015443141541² (a number of 25 digits) contains 22 as substring.

Together with 1015443141539, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1015443141497 and 1015443141506.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1015443141341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507721570770 + 507721570771.

It is an arithmetic number, because the mean of its divisors is an integer number (507721570771).

Almost surely, 2^{1015443141541} is an apocalyptic number.

It is an amenable number.

1015443141541 is a deficient number, since it is larger than the sum of its proper divisors (1).

1015443141541 is an equidigital number, since it uses as much as digits as its factorization.

1015443141541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19200, while the sum is 34.

Adding to 1015443141541 its reverse (1451413445101), we get a palindrome (2466856586642).

The spelling of 1015443141541 in words is "one trillion, fifteen billion, four hundred forty-three million, one hundred forty-one thousand, five hundred forty-one".