101642333130 has 96 divisors (see below), whose sum is σ = 284984009856. Its totient is φ = 24985763712.

The previous prime is 101642333123. The next prime is 101642333167. The reversal of 101642333130 is 31333246101.

101642333130 is a `hidden beast` number, since 1 + 0 + 1 + 642 + 3 + 3 + 3 + 13 + 0 = 666.

101642333130 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 101642333094 and 101642333103.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 810849 + ... + 927771.

It is an arithmetic number, because the mean of its divisors is an integer number (2968583436).

Almost surely, 2^101642333130 is an apocalyptic number.

101642333130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 101642333130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (142492004928).

101642333130 is an abundant number, since it is smaller than the sum of its proper divisors (183341676726).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101642333130 is a wasteful number, since it uses less digits than its factorization.

101642333130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 117692 (or 117689 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 27.

Adding to 101642333130 its reverse (31333246101), we get a palindrome (132975579231).

The spelling of 101642333130 in words is "one hundred one billion, six hundred forty-two million, three hundred thirty-three thousand, one hundred thirty".