Base | Representation |
---|---|
bin | 10010111100001010… |
… | …01001101100110110 |
3 | 222020122112100210021 |
4 | 21132011021230312 |
5 | 131311043441400 |
6 | 4400554515354 |
7 | 506660330614 |
oct | 113605115466 |
9 | 28218470707 |
10 | 10168343350 |
11 | 4348845950 |
12 | 1b79435b5a |
13 | c6083c719 |
14 | 6c66646b4 |
15 | 3e7a6271a |
hex | 25e149b36 |
10168343350 has 48 divisors (see below), whose sum is σ = 20643433200. Its totient is φ = 3695619200.
The previous prime is 10168343329. The next prime is 10168343351. The reversal of 10168343350 is 5334386101.
10168343350 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10168343351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1398324 + ... + 1405576.
It is an arithmetic number, because the mean of its divisors is an integer number (430071525).
Almost surely, 210168343350 is an apocalyptic number.
10168343350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
10168343350 is an abundant number, since it is smaller than the sum of its proper divisors (10475089850).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10168343350 is a wasteful number, since it uses less digits than its factorization.
10168343350 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9825 (or 9820 counting only the distinct ones).
The product of its (nonzero) digits is 25920, while the sum is 34.
The spelling of 10168343350 in words is "ten billion, one hundred sixty-eight million, three hundred forty-three thousand, three hundred fifty".
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