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102113030231957 is a prime number
BaseRepresentation
bin10111001101111100001010…
…111001001101011110010101
3111101112220120122111002102002
4113031330022321031132111
5101341004441214410312
61001102024541525045
730336265036566263
oct2715741271153625
9441486518432362
10102113030231957
112a5999905371a8
12b552233273785
1344c92a9915174
141b304230bb433
15bc12da90b4c2
hex5cdf0ae4d795

102113030231957 has 2 divisors, whose sum is σ = 102113030231958. Its totient is φ = 102113030231956.

The previous prime is 102113030231917. The next prime is 102113030231959. The reversal of 102113030231957 is 759132030311201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87574297636996 + 14538732594961 = 9358114^2 + 3812969^2 .

It is a cyclic number.

It is not a de Polignac number, because 102113030231957 - 210 = 102113030230933 is a prime.

Together with 102113030231959, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 102113030231957.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102113030231959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51056515115978 + 51056515115979.

It is an arithmetic number, because the mean of its divisors is an integer number (51056515115979).

Almost surely, 2102113030231957 is an apocalyptic number.

It is an amenable number.

102113030231957 is a deficient number, since it is larger than the sum of its proper divisors (1).

102113030231957 is an equidigital number, since it uses as much as digits as its factorization.

102113030231957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34020, while the sum is 38.

The spelling of 102113030231957 in words is "one hundred two trillion, one hundred thirteen billion, thirty million, two hundred thirty-one thousand, nine hundred fifty-seven".