10211313120130 has 8 divisors (see below), whose sum is σ = 18380363616252. Its totient is φ = 4084525248048.

The previous prime is 10211313120077. The next prime is 10211313120139. The reversal of 10211313120130 is 3102131311201.

It can be written as a sum of positive squares in 2 ways, for example, as 10206996235921 + 4316884209 = 3194839^2 + 65703^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×10211313120130² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10211313120098 and 10211313120107.

It is not an unprimeable number, because it can be changed into a prime (10211313120139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 510565655997 + ... + 510565656016.

Almost surely, 2^{10211313120130} is an apocalyptic number.

10211313120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

10211313120130 is a deficient number, since it is larger than the sum of its proper divisors (8169050496122).

10211313120130 is a wasteful number, since it uses less digits than its factorization.

10211313120130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1021131312020.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 10211313120130 its reverse (3102131311201), we get a palindrome (13313444431331).

The spelling of 10211313120130 in words is "ten trillion, two hundred eleven billion, three hundred thirteen million, one hundred twenty thousand, one hundred thirty".