Base | Representation |
---|---|
bin | 101111100011001101… |
… | …1010101001100110100 |
3 | 100202120110012011122020 |
4 | 1133012123111030310 |
5 | 3133112001120200 |
6 | 114524334233140 |
7 | 10243314511533 |
oct | 1370633251464 |
9 | 322513164566 |
10 | 102113301300 |
11 | 3a3403296aa |
12 | 179596557b0 |
13 | 98245a699a |
14 | 4d299b031a |
15 | 29c9a2cea0 |
hex | 17c66d5334 |
102113301300 has 36 divisors (see below), whose sum is σ = 295447819296. Its totient is φ = 27230213600.
The previous prime is 102113301299. The next prime is 102113301317. The reversal of 102113301300 is 3103311201.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 102113301300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 170188536 + ... + 170189135.
Almost surely, 2102113301300 is an apocalyptic number.
102113301300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
102113301300 is an abundant number, since it is smaller than the sum of its proper divisors (193334517996).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
102113301300 is a wasteful number, since it uses less digits than its factorization.
102113301300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 340377688 (or 340377681 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 102113301300 its reverse (3103311201), we get a palindrome (105216612501).
Subtracting from 102113301300 its reverse (3103311201), we obtain a palindrome (99009990099).
The spelling of 102113301300 in words is "one hundred two billion, one hundred thirteen million, three hundred one thousand, three hundred".
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