Base | Representation |
---|---|
bin | 1001010010011011100100… |
… | …0111100100100101111111 |
3 | 1100011021120202221102111222 |
4 | 2110212321013210211333 |
5 | 2314304133204014242 |
6 | 33415234545503555 |
7 | 2102544621350411 |
oct | 224467107444577 |
9 | 40137522842458 |
10 | 10212243032447 |
11 | 3287a95a60755 |
12 | 118b24b641bbb |
13 | 591019a823a1 |
14 | 2743bd2129b1 |
15 | 12a99d1425d2 |
hex | 949b91e497f |
10212243032447 has 2 divisors, whose sum is σ = 10212243032448. Its totient is φ = 10212243032446.
The previous prime is 10212243032423. The next prime is 10212243032449. The reversal of 10212243032447 is 74423034221201.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10212243032447 is a prime.
Together with 10212243032449, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10212243032449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106121516223 + 5106121516224.
It is an arithmetic number, because the mean of its divisors is an integer number (5106121516224).
Almost surely, 210212243032447 is an apocalyptic number.
10212243032447 is a deficient number, since it is larger than the sum of its proper divisors (1).
10212243032447 is an equidigital number, since it uses as much as digits as its factorization.
10212243032447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 10212243032447 its reverse (74423034221201), we get a palindrome (84635277253648).
The spelling of 10212243032447 in words is "ten trillion, two hundred twelve billion, two hundred forty-three million, thirty-two thousand, four hundred forty-seven".
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