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10231311300 = 22352731157163
BaseRepresentation
bin10011000011101010…
…10110101111000100
3222102001000110120120
421201311112233010
5131423203430200
64411124301540
7511353465630
oct114165265704
928361013516
1010231311300
114380343681
121b965418b0
13c708b8572
146d0b75dc0
153ed34e9a0
hex261d56bc4

10231311300 has 144 divisors (see below), whose sum is σ = 34923098112. Its totient is φ = 2263132800.

The previous prime is 10231311271. The next prime is 10231311301. The reversal of 10231311300 is 311313201.

10231311300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 10231311300.

It is not an unprimeable number, because it can be changed into a prime (10231311301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 13482 + ... + 143681.

Almost surely, 210231311300 is an apocalyptic number.

10231311300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10231311300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17461549056).

10231311300 is an abundant number, since it is smaller than the sum of its proper divisors (24691786812).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10231311300 is a wasteful number, since it uses less digits than its factorization.

10231311300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 157218 (or 157211 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10231311300 its reverse (311313201), we get a palindrome (10542624501).

The spelling of 10231311300 in words is "ten billion, two hundred thirty-one million, three hundred eleven thousand, three hundred".

Divisors: 1 2 3 4 5 6 7 10 12 14 15 20 21 25 28 30 31 35 42 50 60 62 70 75 84 93 100 105 124 140 150 155 175 186 210 217 300 310 350 372 420 434 465 525 620 651 700 775 868 930 1050 1085 1302 1550 1860 2100 2170 2325 2604 3100 3255 4340 4650 5425 6510 9300 10850 13020 16275 21700 32550 65100 157163 314326 471489 628652 785815 942978 1100141 1571630 1885956 2200282 2357445 3143260 3300423 3929075 4400564 4714890 4872053 5500705 6600846 7858150 9429780 9744106 11001410 11787225 13201692 14616159 15716300 16502115 19488212 22002820 23574450 24360265 27503525 29232318 33004230 34104371 47148900 48720530 55007050 58464636 66008460 68208742 73080795 82510575 97441060 102313113 110014100 121801325 136417484 146161590 165021150 170521855 204626226 243602650 292323180 330042300 341043710 365403975 409252452 487205300 511565565 682087420 730807950 852609275 1023131130 1461615900 1705218550 2046262260 2557827825 3410437100 5115655650 10231311300