Base | Representation |
---|---|
bin | 11101110010010000001… |
… | …00010101011100100101 |
3 | 10121211121021221022122021 |
4 | 32321020010111130211 |
5 | 113231421243444141 |
6 | 2102052040103141 |
7 | 133640041424131 |
oct | 16711004253445 |
9 | 3554537838567 |
10 | 1023411312421 |
11 | 365032007483 |
12 | 146416464ab1 |
13 | 7567962a324 |
14 | 377678023c1 |
15 | 1b94bc216d1 |
hex | ee48115725 |
1023411312421 has 2 divisors, whose sum is σ = 1023411312422. Its totient is φ = 1023411312420.
The previous prime is 1023411312419. The next prime is 1023411312449. The reversal of 1023411312421 is 1242131143201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 853905364900 + 169505947521 = 924070^2 + 411711^2 .
It is a cyclic number.
It is not a de Polignac number, because 1023411312421 - 21 = 1023411312419 is a prime.
Together with 1023411312419, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1023411310421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 511705656210 + 511705656211.
It is an arithmetic number, because the mean of its divisors is an integer number (511705656211).
Almost surely, 21023411312421 is an apocalyptic number.
It is an amenable number.
1023411312421 is a deficient number, since it is larger than the sum of its proper divisors (1).
1023411312421 is an equidigital number, since it uses as much as digits as its factorization.
1023411312421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1023411312421 its reverse (1242131143201), we get a palindrome (2265542455622).
The spelling of 1023411312421 in words is "one trillion, twenty-three billion, four hundred eleven million, three hundred twelve thousand, four hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •