Base | Representation |
---|---|
bin | 1001010100001111110000… |
… | …1100101000111010011111 |
3 | 1100021021002110202101021002 |
4 | 2111003330030220322133 |
5 | 2320312022400033112 |
6 | 33441433535300515 |
7 | 2105030552425313 |
oct | 225037414507237 |
9 | 40237073671232 |
10 | 10243433205407 |
11 | 329a240aa92a6 |
12 | 11952b507a73b |
13 | 593c4a8aaa2c |
14 | 275adb74db43 |
15 | 12b6c64b51c2 |
hex | 950fc328e9f |
10243433205407 has 2 divisors, whose sum is σ = 10243433205408. Its totient is φ = 10243433205406.
The previous prime is 10243433205331. The next prime is 10243433205409. The reversal of 10243433205407 is 70450233434201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10243433205407 - 216 = 10243433139871 is a prime.
Together with 10243433205409, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10243433205409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5121716602703 + 5121716602704.
It is an arithmetic number, because the mean of its divisors is an integer number (5121716602704).
Almost surely, 210243433205407 is an apocalyptic number.
10243433205407 is a deficient number, since it is larger than the sum of its proper divisors (1).
10243433205407 is an equidigital number, since it uses as much as digits as its factorization.
10243433205407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 241920, while the sum is 38.
Adding to 10243433205407 its reverse (70450233434201), we get a palindrome (80693666639608).
The spelling of 10243433205407 in words is "ten trillion, two hundred forty-three billion, four hundred thirty-three million, two hundred five thousand, four hundred seven".
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