Base | Representation |
---|---|
bin | 101111111101111110… |
… | …1000000111000001111 |
3 | 100211220000222102101021 |
4 | 1133323331000320033 |
5 | 3141431344322112 |
6 | 115153414055011 |
7 | 10304500542016 |
oct | 1377375007017 |
9 | 324800872337 |
10 | 103011323407 |
11 | 3a76122aa33 |
12 | 17b6a34a467 |
13 | 993865a005 |
14 | 4db2d73a7d |
15 | 2a2d7b8907 |
hex | 17fbf40e0f |
103011323407 has 2 divisors, whose sum is σ = 103011323408. Its totient is φ = 103011323406.
The previous prime is 103011323329. The next prime is 103011323447. The reversal of 103011323407 is 704323110301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103011323407 - 219 = 103010799119 is a prime.
It is a super-2 number, since 2×1030113234072 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103011323447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51505661703 + 51505661704.
It is an arithmetic number, because the mean of its divisors is an integer number (51505661704).
Almost surely, 2103011323407 is an apocalyptic number.
103011323407 is a deficient number, since it is larger than the sum of its proper divisors (1).
103011323407 is an equidigital number, since it uses as much as digits as its factorization.
103011323407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 103011323407 its reverse (704323110301), we get a palindrome (807334433708).
The spelling of 103011323407 in words is "one hundred three billion, eleven million, three hundred twenty-three thousand, four hundred seven".
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