Base | Representation |
---|---|
bin | 101111111101111110… |
… | …1000000111000110111 |
3 | 100211220000222102102202 |
4 | 1133323331000320313 |
5 | 3141431344322242 |
6 | 115153414055115 |
7 | 10304500542104 |
oct | 1377375007067 |
9 | 324800872382 |
10 | 103011323447 |
11 | 3a76122aa6a |
12 | 17b6a34a49b |
13 | 993865a036 |
14 | 4db2d73aab |
15 | 2a2d7b8932 |
hex | 17fbf40e37 |
103011323447 has 2 divisors, whose sum is σ = 103011323448. Its totient is φ = 103011323446.
The previous prime is 103011323407. The next prime is 103011323449. The reversal of 103011323447 is 744323110301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103011323447 - 210 = 103011322423 is a prime.
It is a super-2 number, since 2×1030113234472 (a number of 23 digits) contains 22 as substring.
Together with 103011323449, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103011323449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51505661723 + 51505661724.
It is an arithmetic number, because the mean of its divisors is an integer number (51505661724).
Almost surely, 2103011323447 is an apocalyptic number.
103011323447 is a deficient number, since it is larger than the sum of its proper divisors (1).
103011323447 is an equidigital number, since it uses as much as digits as its factorization.
103011323447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 103011323447 its reverse (744323110301), we get a palindrome (847334433748).
The spelling of 103011323447 in words is "one hundred three billion, eleven million, three hundred twenty-three thousand, four hundred forty-seven".
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