Base | Representation |
---|---|
bin | 11101111110111110100… |
… | …10010110011011000000 |
3 | 10122111020102112221000111 |
4 | 32333133102112123000 |
5 | 113334414242011334 |
6 | 2105142013401104 |
7 | 134301250450150 |
oct | 16773722263300 |
9 | 3574212487014 |
10 | 1030243313344 |
11 | 367a18545933 |
12 | 147802499194 |
13 | 761c7ba191b |
14 | 37c14d0a760 |
15 | 1bbeb903064 |
hex | efdf4966c0 |
1030243313344 has 28 divisors (see below), whose sum is σ = 2336444658064. Its totient is φ = 441532848384.
The previous prime is 1030243313299. The next prime is 1030243313383. The reversal of 1030243313344 is 4433133420301.
It is a tau number, because it is divible by the number of its divisors (28).
It is a super-2 number, since 2×10302433133442 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1149824679 + ... + 1149825574.
Almost surely, 21030243313344 is an apocalyptic number.
1030243313344 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
1030243313344 is an abundant number, since it is smaller than the sum of its proper divisors (1306201344720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1030243313344 is an equidigital number, since it uses as much as digits as its factorization.
1030243313344 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2299650272 (or 2299650262 counting only the distinct ones).
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 1030243313344 its reverse (4433133420301), we get a palindrome (5463376733645).
The spelling of 1030243313344 in words is "one trillion, thirty billion, two hundred forty-three million, three hundred thirteen thousand, three hundred forty-four".
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