Search a number
-
+
1031001011231 is a prime number
BaseRepresentation
bin11110000000011000111…
…00101111010000011111
310122120012020021222010012
433000030130233100133
5113342442224324411
62105345121433435
7134326110666662
oct17001434572037
93576166258105
101031001011231
11368277213534
1214799419b87b
13762b8b63179
1437c877c36d9
151bc431c118b
hexf00c72f41f

1031001011231 has 2 divisors, whose sum is σ = 1031001011232. Its totient is φ = 1031001011230.

The previous prime is 1031001011191. The next prime is 1031001011233. The reversal of 1031001011231 is 1321101001301.

It is a happy number.

1031001011231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1031001011231 is a prime.

It is a super-2 number, since 2×10310010112312 (a number of 25 digits) contains 22 as substring.

Together with 1031001011233, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1031001011233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515500505615 + 515500505616.

It is an arithmetic number, because the mean of its divisors is an integer number (515500505616).

Almost surely, 21031001011231 is an apocalyptic number.

1031001011231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031001011231 is an equidigital number, since it uses as much as digits as its factorization.

1031001011231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 1031001011231 its reverse (1321101001301), we get a palindrome (2352102012532).

The spelling of 1031001011231 in words is "one trillion, thirty-one billion, one million, eleven thousand, two hundred thirty-one".