Base | Representation |
---|---|
bin | 11110000000011000111… |
… | …00101111010000011111 |
3 | 10122120012020021222010012 |
4 | 33000030130233100133 |
5 | 113342442224324411 |
6 | 2105345121433435 |
7 | 134326110666662 |
oct | 17001434572037 |
9 | 3576166258105 |
10 | 1031001011231 |
11 | 368277213534 |
12 | 14799419b87b |
13 | 762b8b63179 |
14 | 37c877c36d9 |
15 | 1bc431c118b |
hex | f00c72f41f |
1031001011231 has 2 divisors, whose sum is σ = 1031001011232. Its totient is φ = 1031001011230.
The previous prime is 1031001011191. The next prime is 1031001011233. The reversal of 1031001011231 is 1321101001301.
It is a happy number.
1031001011231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1031001011231 is a prime.
It is a super-2 number, since 2×10310010112312 (a number of 25 digits) contains 22 as substring.
Together with 1031001011233, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1031001011233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515500505615 + 515500505616.
It is an arithmetic number, because the mean of its divisors is an integer number (515500505616).
Almost surely, 21031001011231 is an apocalyptic number.
1031001011231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031001011231 is an equidigital number, since it uses as much as digits as its factorization.
1031001011231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 1031001011231 its reverse (1321101001301), we get a palindrome (2352102012532).
The spelling of 1031001011231 in words is "one trillion, thirty-one billion, one million, eleven thousand, two hundred thirty-one".
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