Base | Representation |
---|---|
bin | 10011001101000011… |
… | …00110110000001111 |
3 | 222121112010021202201 |
4 | 21212201212300033 |
5 | 132103331120421 |
6 | 4423015302331 |
7 | 513330503446 |
oct | 114641466017 |
9 | 28545107681 |
10 | 10310020111 |
11 | 4410812786 |
12 | 1bb897a9a7 |
13 | c83cb6021 |
14 | 6db3c3d5d |
15 | 4051eab91 |
hex | 266866c0f |
10310020111 has 2 divisors, whose sum is σ = 10310020112. Its totient is φ = 10310020110.
The previous prime is 10310020109. The next prime is 10310020117. The reversal of 10310020111 is 11102001301.
It is a weak prime.
It is an emirp because it is prime and its reverse (11102001301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10310020111 - 21 = 10310020109 is a prime.
It is a super-3 number, since 3×103100201113 (a number of 31 digits) contains 333 as substring.
Together with 10310020109, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10310020117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155010055 + 5155010056.
It is an arithmetic number, because the mean of its divisors is an integer number (5155010056).
Almost surely, 210310020111 is an apocalyptic number.
10310020111 is a deficient number, since it is larger than the sum of its proper divisors (1).
10310020111 is an equidigital number, since it uses as much as digits as its factorization.
10310020111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 10.
Adding to 10310020111 its reverse (11102001301), we get a palindrome (21412021412).
The spelling of 10310020111 in words is "ten billion, three hundred ten million, twenty thousand, one hundred eleven".
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