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103101122199983 is a prime number
BaseRepresentation
bin10111011100010100011001…
…110000111100000110101111
3111112001101000110211210221212
4113130110121300330012233
5102003202044240344413
61003140000205545035
730500544631002035
oct2734243160740657
9445041013753855
10103101122199983
112a93aa38706456
12b69183127517b
13456b517b09b2b
141b66199c06555
15bdbd6ba1bca8
hex5dc519c3c1af

103101122199983 has 2 divisors, whose sum is σ = 103101122199984. Its totient is φ = 103101122199982.

The previous prime is 103101122199973. The next prime is 103101122200033. The reversal of 103101122199983 is 389991221101301.

It is a happy number.

It is an a-pointer prime, because the next prime (103101122200033) can be obtained adding 103101122199983 to its sum of digits (50).

It is a weak prime.

It is an emirp because it is prime and its reverse (389991221101301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103101122199983 - 230 = 103100048458159 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103101122199953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51550561099991 + 51550561099992.

It is an arithmetic number, because the mean of its divisors is an integer number (51550561099992).

Almost surely, 2103101122199983 is an apocalyptic number.

103101122199983 is a deficient number, since it is larger than the sum of its proper divisors (1).

103101122199983 is an equidigital number, since it uses as much as digits as its factorization.

103101122199983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 209952, while the sum is 50.

The spelling of 103101122199983 in words is "one hundred three trillion, one hundred one billion, one hundred twenty-two million, one hundred ninety-nine thousand, nine hundred eighty-three".