Base | Representation |
---|---|
bin | 11110000000110010001… |
… | …01111000011000111010 |
3 | 10122120202000102100221110 |
4 | 33000121011320120322 |
5 | 113343411024420010 |
6 | 2105422140021150 |
7 | 134334264631011 |
oct | 17003105703072 |
9 | 3576660370843 |
10 | 1031213123130 |
11 | 368375a19323 |
12 | 147a332317b6 |
13 | 76320a9b378 |
14 | 37ca7a39a78 |
15 | 1bc56b1e120 |
hex | f01917863a |
1031213123130 has 32 divisors (see below), whose sum is σ = 2474945352000. Its totient is φ = 274986404352.
The previous prime is 1031213123123. The next prime is 1031213123153. The reversal of 1031213123130 is 313213121301.
It is a happy number.
It is a super-3 number, since 3×10312131231303 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1031213123097 and 1031213123106.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2526021 + ... + 2905719.
It is an arithmetic number, because the mean of its divisors is an integer number (77342042250).
Almost surely, 21031213123130 is an apocalyptic number.
1031213123130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1031213123130 is an abundant number, since it is smaller than the sum of its proper divisors (1443732228870).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1031213123130 is a wasteful number, since it uses less digits than its factorization.
1031213123130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 470238.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 1031213123130 its reverse (313213121301), we get a palindrome (1344426244431).
The spelling of 1031213123130 in words is "one trillion, thirty-one billion, two hundred thirteen million, one hundred twenty-three thousand, one hundred thirty".
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