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103121312320303 is a prime number
BaseRepresentation
bin10111011100100111001101…
…001100001000101100101111
3111112010022010120010012020221
4113130213031030020230233
5102004014421423222203
61003153135450152211
730502161152124424
oct2734471514105457
9445108116105227
10103121312320303
112a94855948a702
12b695726a22667
1345703b49bcba4
141b6715345bd4b
15bdc64e2deabd
hex5dc9cd308b2f

103121312320303 has 2 divisors, whose sum is σ = 103121312320304. Its totient is φ = 103121312320302.

The previous prime is 103121312320297. The next prime is 103121312320309. The reversal of 103121312320303 is 303023213121301.

It is a balanced prime because it is at equal distance from previous prime (103121312320297) and next prime (103121312320309).

It is a cyclic number.

It is not a de Polignac number, because 103121312320303 - 213 = 103121312312111 is a prime.

It is a super-2 number, since 2×1031213123203032 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103121312320309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51560656160151 + 51560656160152.

It is an arithmetic number, because the mean of its divisors is an integer number (51560656160152).

Almost surely, 2103121312320303 is an apocalyptic number.

103121312320303 is a deficient number, since it is larger than the sum of its proper divisors (1).

103121312320303 is an equidigital number, since it uses as much as digits as its factorization.

103121312320303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 103121312320303 its reverse (303023213121301), we get a palindrome (406144525441604).

The spelling of 103121312320303 in words is "one hundred three trillion, one hundred twenty-one billion, three hundred twelve million, three hundred twenty thousand, three hundred three".