Base | Representation |
---|---|
bin | 1001011000010011101010… |
… | …1111011110000110111111 |
3 | 1100111221011210001101101021 |
4 | 2112010322233132012333 |
5 | 2322432414203002234 |
6 | 33533453010525011 |
7 | 2113050521412541 |
oct | 226047257360677 |
9 | 40457153041337 |
10 | 10313202000319 |
11 | 3316893734589 |
12 | 11a6926596767 |
13 | 59a6b916372a |
14 | 27923977d691 |
15 | 12d40b6559b4 |
hex | 9613abde1bf |
10313202000319 has 2 divisors, whose sum is σ = 10313202000320. Its totient is φ = 10313202000318.
The previous prime is 10313202000209. The next prime is 10313202000341. The reversal of 10313202000319 is 91300020231301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10313202000319 - 225 = 10313168445887 is a prime.
It is a super-2 number, since 2×103132020003192 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10313202000293 and 10313202000302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10313202000359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156601000159 + 5156601000160.
It is an arithmetic number, because the mean of its divisors is an integer number (5156601000160).
Almost surely, 210313202000319 is an apocalyptic number.
10313202000319 is a deficient number, since it is larger than the sum of its proper divisors (1).
10313202000319 is an equidigital number, since it uses as much as digits as its factorization.
10313202000319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
The spelling of 10313202000319 in words is "ten trillion, three hundred thirteen billion, two hundred two million, three hundred nineteen", and thus it is an aban number.
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