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1031344032031 is a prime number
BaseRepresentation
bin11110000001000001110…
…01010000100100011111
310122121002010202020012021
433000200321100210133
5113344143033011111
62105443133521011
7134340444425425
oct17004071204437
93577063666167
101031344032031
113684329010a5
12147a6b043167
1376341c44761
1437cbb195115
151bc6337bd71
hexf020e5091f

1031344032031 has 2 divisors, whose sum is σ = 1031344032032. Its totient is φ = 1031344032030.

The previous prime is 1031344032029. The next prime is 1031344032097. The reversal of 1031344032031 is 1302304431301.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1031344032031 - 21 = 1031344032029 is a prime.

It is a super-2 number, since 2×10313440320312 (a number of 25 digits) contains 22 as substring.

Together with 1031344032029, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1031344031987 and 1031344032005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1031344032001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515672016015 + 515672016016.

It is an arithmetic number, because the mean of its divisors is an integer number (515672016016).

Almost surely, 21031344032031 is an apocalyptic number.

1031344032031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031344032031 is an equidigital number, since it uses as much as digits as its factorization.

1031344032031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1031344032031 its reverse (1302304431301), we get a palindrome (2333648463332).

The spelling of 1031344032031 in words is "one trillion, thirty-one billion, three hundred forty-four million, thirty-two thousand, thirty-one".