Base | Representation |
---|---|
bin | 1001011000011110100011… |
… | …0010111001111110110101 |
3 | 1100112012201021210200011012 |
4 | 2112013220302321332311 |
5 | 2323004404231332001 |
6 | 33535054443322005 |
7 | 2113213060230236 |
oct | 226075062717665 |
9 | 40465637720135 |
10 | 10316122136501 |
11 | 3318052007075 |
12 | 11a7400520305 |
13 | 59aa6313486c |
14 | 27943551708d |
15 | 12d52cbc12bb |
hex | 961e8cb9fb5 |
10316122136501 has 2 divisors, whose sum is σ = 10316122136502. Its totient is φ = 10316122136500.
The previous prime is 10316122136429. The next prime is 10316122136519. The reversal of 10316122136501 is 10563122161301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10285323641476 + 30798495025 = 3207074^2 + 175495^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10316122136501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10316122136101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5158061068250 + 5158061068251.
It is an arithmetic number, because the mean of its divisors is an integer number (5158061068251).
Almost surely, 210316122136501 is an apocalyptic number.
It is an amenable number.
10316122136501 is a deficient number, since it is larger than the sum of its proper divisors (1).
10316122136501 is an equidigital number, since it uses as much as digits as its factorization.
10316122136501 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 32.
Adding to 10316122136501 its reverse (10563122161301), we get a palindrome (20879244297802).
The spelling of 10316122136501 in words is "ten trillion, three hundred sixteen billion, one hundred twenty-two million, one hundred thirty-six thousand, five hundred one".
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