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10322123131120 = 245198297818473
BaseRepresentation
bin1001011000110100111001…
…1110111000100011110000
31100112210012111201210012011
42112031032132320203300
52323104202010143440
633541530133412304
72113514555650333
oct226151636704360
940483174653164
1010322123131120
11331a651457159
1211a85b619a094
1359b4ab48b258
1427984450461a
1512d77e9539ea
hex9634e7b88f0

10322123131120 has 80 divisors (see below), whose sum is σ = 25265113777440. Its totient is φ = 3911065178112.

The previous prime is 10322123131093. The next prime is 10322123131123. The reversal of 10322123131120 is 2113132122301.

10322123131120 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (80).

It is a super-4 number, since 4×103221231311204 (a number of 53 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10322123131091 and 10322123131100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10322123131123) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12202204 + ... + 13020676.

It is an arithmetic number, because the mean of its divisors is an integer number (315813922218).

Almost surely, 210322123131120 is an apocalyptic number.

10322123131120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

10322123131120 is an abundant number, since it is smaller than the sum of its proper divisors (14942990646320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10322123131120 is a wasteful number, since it uses less digits than its factorization.

10322123131120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 826802 (or 826796 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 10322123131120 its reverse (2113132122301), we get a palindrome (12435255253421).

The spelling of 10322123131120 in words is "ten trillion, three hundred twenty-two billion, one hundred twenty-three million, one hundred thirty-one thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 16 19 20 38 40 76 80 95 152 190 304 380 760 1520 8297 16594 33188 41485 66376 82970 132752 157643 165940 315286 331880 630572 663760 788215 818473 1261144 1576430 1636946 2522288 3152860 3273892 4092365 6305720 6547784 8184730 12611440 13095568 15550987 16369460 31101974 32738920 62203948 65477840 77754935 124407896 155509870 248815792 311019740 622039480 1244078960 6790870481 13581740962 27163481924 33954352405 54326963848 67908704810 108653927696 129026539139 135817409620 258053078278 271634819240 516106156556 543269638480 645132695695 1032212313112 1290265391390 2064424626224 2580530782780 5161061565560 10322123131120