Base | Representation |
---|---|
bin | 110000000101001011… |
… | …1011110001000100000 |
3 | 100212111212222222101101 |
4 | 1200022113132020200 |
5 | 3142430300440000 |
6 | 115233413044144 |
7 | 10313465131453 |
oct | 1401227361040 |
9 | 325455888341 |
10 | 103253140000 |
11 | 3a87578435a |
12 | 18017326654 |
13 | 997679595a |
14 | 4dd711d49a |
15 | 2a44b32e6a |
hex | 180a5de220 |
103253140000 has 120 divisors (see below), whose sum is σ = 255304526400. Its totient is φ = 41092128000.
The previous prime is 103253139971. The next prime is 103253140093. The reversal of 103253140000 is 41352301.
It is a super-3 number, since 3×1032531400003 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 103253140000.
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 3967029 + ... + 3992971.
It is an arithmetic number, because the mean of its divisors is an integer number (2127537720).
Almost surely, 2103253140000 is an apocalyptic number.
103253140000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 103253140000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (127652263200).
103253140000 is an abundant number, since it is smaller than the sum of its proper divisors (152051386400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
103253140000 is an equidigital number, since it uses as much as digits as its factorization.
103253140000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26172 (or 26149 counting only the distinct ones).
The product of its (nonzero) digits is 360, while the sum is 19.
Adding to 103253140000 its reverse (41352301), we get a palindrome (103294492301).
It can be divided in two parts, 103253 and 140000, that added together give a triangular number (243253 = T697).
The spelling of 103253140000 in words is "one hundred three billion, two hundred fifty-three million, one hundred forty thousand".
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