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103553441350 = 2522071068827
BaseRepresentation
bin110000001110001000…
…1000001111001000110
3100220021211001212101121
41200130101001321012
53144034140110400
6115323301344154
710324102504552
oct1403421017106
9326254055347
10103553441350
113aa0a244197
121809ba0805a
1399c3a6a968
145024d70862
152a611a121a
hex181c441e46

103553441350 has 12 divisors (see below), whose sum is σ = 192609401004. Its totient is φ = 41421376520.

The previous prime is 103553441333. The next prime is 103553441353. The reversal of 103553441350 is 53144355301.

It is a super-3 number, since 3×1035534413503 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103553441353) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1035534364 + ... + 1035534463.

It is an arithmetic number, because the mean of its divisors is an integer number (16050783417).

Almost surely, 2103553441350 is an apocalyptic number.

103553441350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

103553441350 is a deficient number, since it is larger than the sum of its proper divisors (89055959654).

103553441350 is a wasteful number, since it uses less digits than its factorization.

103553441350 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2071068839 (or 2071068834 counting only the distinct ones).

The product of its (nonzero) digits is 54000, while the sum is 34.

Adding to 103553441350 its reverse (53144355301), we get a palindrome (156697796651).

The spelling of 103553441350 in words is "one hundred three billion, five hundred fifty-three million, four hundred forty-one thousand, three hundred fifty".

Divisors: 1 2 5 10 25 50 2071068827 4142137654 10355344135 20710688270 51776720675 103553441350