10401310181 has 2 divisors, whose sum is σ = 10401310182. Its totient is φ = 10401310180.

The previous prime is 10401310133. The next prime is 10401310267. The reversal of 10401310181 is 18101310401.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9870422500 + 530887681 = 99350^2 + 23041^2 .

It is a cyclic number.

It is not a de Polignac number, because 10401310181 - 2¹⁸ = 10401048037 is a prime.

It is a super-2 number, since 2×10401310181² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10401300181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5200655090 + 5200655091.

It is an arithmetic number, because the mean of its divisors is an integer number (5200655091).

Almost surely, 2^10401310181 is an apocalyptic number.

It is an amenable number.

10401310181 is a deficient number, since it is larger than the sum of its proper divisors (1).

10401310181 is an equidigital number, since it uses as much as digits as its factorization.

10401310181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 10401310181 its reverse (18101310401), we get a palindrome (28502620582).

The spelling of 10401310181 in words is "ten billion, four hundred one million, three hundred ten thousand, one hundred eighty-one".