1040132500 has 120 divisors (see below), whose sum is σ = 2511321120. Its totient is φ = 373680000.

The previous prime is 1040132497. The next prime is 1040132501. The reversal of 1040132500 is 52310401.

It is a super-3 number, since 3×1040132500³ (a number of 28 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1040132501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 2997327 + ... + 2997673.

It is an arithmetic number, because the mean of its divisors is an integer number (20927676).

Almost surely, 2^1040132500 is an apocalyptic number.

1040132500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1040132500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1255660560).

1040132500 is an abundant number, since it is smaller than the sum of its proper divisors (1471188620).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1040132500 is a wasteful number, since it uses less digits than its factorization.

1040132500 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 491 (or 474 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 1040132500 is about 32251.0852530578. The cubic root of 1040132500 is about 1013.2024287947.

Adding to 1040132500 its reverse (52310401), we get a palindrome (1092442901).

The spelling of 1040132500 in words is "one billion, forty million, one hundred thirty-two thousand, five hundred".