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10432203021941 is a prime number
BaseRepresentation
bin1001011111001110111111…
…0000010101111001110101
31100221022100011110122011112
42113303233300111321311
52331410122433200231
634104253215444405
72124462500410541
oct227635760257165
940838304418145
1010432203021941
1133622aa703438
1212059b7826705
135a89a23aa91c
14280cc8162a21
15131573a7c92b
hex97cefc15e75

10432203021941 has 2 divisors, whose sum is σ = 10432203021942. Its totient is φ = 10432203021940.

The previous prime is 10432203021907. The next prime is 10432203021943. The reversal of 10432203021941 is 14912030223401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8233003001041 + 2199200020900 = 2869321^2 + 1482970^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10432203021941 is a prime.

It is a Sophie Germain prime.

Together with 10432203021943, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10432203021898 and 10432203021907.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10432203021943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5216101510970 + 5216101510971.

It is an arithmetic number, because the mean of its divisors is an integer number (5216101510971).

Almost surely, 210432203021941 is an apocalyptic number.

It is an amenable number.

10432203021941 is a deficient number, since it is larger than the sum of its proper divisors (1).

10432203021941 is an equidigital number, since it uses as much as digits as its factorization.

10432203021941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 32.

The spelling of 10432203021941 in words is "ten trillion, four hundred thirty-two billion, two hundred three million, twenty-one thousand, nine hundred forty-one".