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1043313334142 = 2432713973649
BaseRepresentation
bin11110010111010100101…
…00100001011101111110
310200201222022002202221212
433023222110201131332
5114043201203143032
62115142545324422
7135243164006102
oct17135224413576
93621868082855
101043313334142
113725151a5a12
1214a24b636712
13774cb91b741
14386d4aa1902
151c214086bb2
hexf2ea52177e

1043313334142 has 24 divisors (see below), whose sum is σ = 1624777801200. Its totient is φ = 502348580160.

The previous prime is 1043313334097. The next prime is 1043313334157. The reversal of 1043313334142 is 2414333133401.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 1043313334099 and 1043313334108.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1724267 + ... + 2249382.

It is an arithmetic number, because the mean of its divisors is an integer number (67699075050).

Almost surely, 21043313334142 is an apocalyptic number.

1043313334142 is a deficient number, since it is larger than the sum of its proper divisors (581464467058).

1043313334142 is an equidigital number, since it uses as much as digits as its factorization.

1043313334142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3973808 (or 3973765 counting only the distinct ones).

The product of its (nonzero) digits is 31104, while the sum is 32.

Adding to 1043313334142 its reverse (2414333133401), we get a palindrome (3457646467543).

The spelling of 1043313334142 in words is "one trillion, forty-three billion, three hundred thirteen million, three hundred thirty-four thousand, one hundred forty-two".

Divisors: 1 2 43 71 86 142 1849 3053 3698 6106 131279 262558 3973649 7947298 170866907 282129079 341733814 564258158 7347277001 12131550397 14694554002 24263100794 521656667071 1043313334142