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104435113817 is a prime number
BaseRepresentation
bin110000101000011010…
…0010101111101011001
3100222120021002110122102
41201100310111331121
53202340342120232
6115550554533145
710354666551326
oct1412064257531
9328507073572
10104435113817
1140321998821
12182a71371b5
139b04618248
1450aa0b9b4d
152ab37ac662
hex1850d15f59

104435113817 has 2 divisors, whose sum is σ = 104435113818. Its totient is φ = 104435113816.

The previous prime is 104435113763. The next prime is 104435113819. The reversal of 104435113817 is 718311534401.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102615152896 + 1819960921 = 320336^2 + 42661^2 .

It is an emirp because it is prime and its reverse (718311534401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 104435113817 - 222 = 104430919513 is a prime.

Together with 104435113819, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (104435113819) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52217556908 + 52217556909.

It is an arithmetic number, because the mean of its divisors is an integer number (52217556909).

Almost surely, 2104435113817 is an apocalyptic number.

It is an amenable number.

104435113817 is a deficient number, since it is larger than the sum of its proper divisors (1).

104435113817 is an equidigital number, since it uses as much as digits as its factorization.

104435113817 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 38.

The spelling of 104435113817 in words is "one hundred four billion, four hundred thirty-five million, one hundred thirteen thousand, eight hundred seventeen".