Base | Representation |
---|---|
bin | 10011011101101111… |
… | …01111110100000101 |
3 | 222222021121010211221 |
4 | 21232313233310011 |
5 | 132400202321432 |
6 | 4444540400341 |
7 | 516650615044 |
oct | 115667576405 |
9 | 28867533757 |
10 | 10450042117 |
11 | 448285a349 |
12 | 20378460b1 |
13 | ca7000398 |
14 | 711c3255b |
15 | 412658b97 |
hex | 26edefd05 |
10450042117 has 2 divisors, whose sum is σ = 10450042118. Its totient is φ = 10450042116.
The previous prime is 10450042093. The next prime is 10450042133. The reversal of 10450042117 is 71124005401.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8395323876 + 2054718241 = 91626^2 + 45329^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10450042117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10450042091 and 10450042100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10450042177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5225021058 + 5225021059.
It is an arithmetic number, because the mean of its divisors is an integer number (5225021059).
Almost surely, 210450042117 is an apocalyptic number.
It is an amenable number.
10450042117 is a deficient number, since it is larger than the sum of its proper divisors (1).
10450042117 is an equidigital number, since it uses as much as digits as its factorization.
10450042117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1120, while the sum is 25.
Adding to 10450042117 its reverse (71124005401), we get a palindrome (81574047518).
The spelling of 10450042117 in words is "ten billion, four hundred fifty million, forty-two thousand, one hundred seventeen".
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