Base | Representation |
---|---|
bin | 110000111100100010… |
… | …1100001101110110111 |
3 | 101001022100100011102212 |
4 | 1201321011201232313 |
5 | 3210231320112002 |
6 | 120142011124035 |
7 | 10410512161166 |
oct | 1417105415667 |
9 | 331270304385 |
10 | 105110707127 |
11 | 40639287aa8 |
12 | 1845544361b |
13 | 9bb15904ba |
14 | 5131add3dd |
15 | 2b02c5d352 |
hex | 1879161bb7 |
105110707127 has 2 divisors, whose sum is σ = 105110707128. Its totient is φ = 105110707126.
The previous prime is 105110707123. The next prime is 105110707129. The reversal of 105110707127 is 721707011501.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 105110707127 - 22 = 105110707123 is a prime.
It is a super-2 number, since 2×1051107071272 (a number of 23 digits) contains 22 as substring.
Together with 105110707129, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 105110707093 and 105110707102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (105110707123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52555353563 + 52555353564.
It is an arithmetic number, because the mean of its divisors is an integer number (52555353564).
Almost surely, 2105110707127 is an apocalyptic number.
105110707127 is a deficient number, since it is larger than the sum of its proper divisors (1).
105110707127 is an equidigital number, since it uses as much as digits as its factorization.
105110707127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3430, while the sum is 32.
Adding to 105110707127 its reverse (721707011501), we get a palindrome (826817718628).
The spelling of 105110707127 in words is "one hundred five billion, one hundred ten million, seven hundred seven thousand, one hundred twenty-seven".
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