Base | Representation |
---|---|
bin | 10011100111011010… |
… | …11000111100110110 |
3 | 1000011221100001112000 |
4 | 21303231120330312 |
5 | 133031442304420 |
6 | 4501000240130 |
7 | 521654556135 |
oct | 116355307466 |
9 | 30157301460 |
10 | 10531213110 |
11 | 4514660310 |
12 | 205aa70046 |
13 | cbaa80762 |
14 | 71c92191c |
15 | 41983e690 |
hex | 273b58f36 |
10531213110 has 128 divisors (see below), whose sum is σ = 30707251200. Its totient is φ = 2547106560.
The previous prime is 10531213073. The next prime is 10531213111. The reversal of 10531213110 is 1131213501.
10531213110 is a `hidden beast` number, since 1 + 0 + 531 + 2 + 131 + 1 + 0 = 666.
It is a super-2 number, since 2×105312131102 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10531213111) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1353411 + ... + 1361169.
It is an arithmetic number, because the mean of its divisors is an integer number (239900400).
Almost surely, 210531213110 is an apocalyptic number.
10531213110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 10531213110, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15353625600).
10531213110 is an abundant number, since it is smaller than the sum of its proper divisors (20176038090).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10531213110 is a wasteful number, since it uses less digits than its factorization.
10531213110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8243 (or 8237 counting only the distinct ones).
The product of its (nonzero) digits is 90, while the sum is 18.
Adding to 10531213110 its reverse (1131213501), we get a palindrome (11662426611).
The spelling of 10531213110 in words is "ten billion, five hundred thirty-one million, two hundred thirteen thousand, one hundred ten".
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