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10534413000 = 233537944449
BaseRepresentation
bin10011100111110011…
…00110001011001000
31000012011100121221110
421303321212023020
5133033302204000
64501153010320
7522024014226
oct116371461310
930164317843
1010534413000
114516446451
12205bb539a0
13cbb631097
1471d115b16
15419c72850
hex273e662c8

10534413000 has 128 divisors (see below), whose sum is σ = 33284160000. Its totient is φ = 2773555200.

The previous prime is 10534412983. The next prime is 10534413017. The reversal of 10534413000 is 31443501.

10534413000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (10534412983) and next prime (10534413017).

It is a super-3 number, since 3×105344130003 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 214776 + ... + 259224.

It is an arithmetic number, because the mean of its divisors is an integer number (260032500).

Almost surely, 210534413000 is an apocalyptic number.

10534413000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10534413000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16642080000).

10534413000 is an abundant number, since it is smaller than the sum of its proper divisors (22749747000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10534413000 is a wasteful number, since it uses less digits than its factorization.

10534413000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44552 (or 44538 counting only the distinct ones).

The product of its (nonzero) digits is 720, while the sum is 21.

Adding to 10534413000 its reverse (31443501), we get a palindrome (10565856501).

The spelling of 10534413000 in words is "ten billion, five hundred thirty-four million, four hundred thirteen thousand".

Divisors: 1 2 3 4 5 6 8 10 12 15 20 24 25 30 40 50 60 75 79 100 120 125 150 158 200 237 250 300 316 375 395 474 500 600 632 750 790 948 1000 1185 1500 1580 1896 1975 2370 3000 3160 3950 4740 5925 7900 9480 9875 11850 15800 19750 23700 29625 39500 44449 47400 59250 79000 88898 118500 133347 177796 222245 237000 266694 355592 444490 533388 666735 888980 1066776 1111225 1333470 1777960 2222450 2666940 3333675 3511471 4444900 5333880 5556125 6667350 7022942 8889800 10534413 11112250 13334700 14045884 16668375 17557355 21068826 22224500 26669400 28091768 33336750 35114710 42137652 44449000 52672065 66673500 70229420 84275304 87786775 105344130 133347000 140458840 175573550 210688260 263360325 351147100 421376520 438933875 526720650 702294200 877867750 1053441300 1316801625 1755735500 2106882600 2633603250 3511471000 5267206500 10534413000